1.How many grams of KCl is in 225 mL of a 0.452 M solution?

2.What volume in mL of 0.555 M solution contains 85.0g Na2SO4?
3.How many grams of CaCl2 would be dissolved in 2.0L of a 0.10 M solution of CaCl2?

Can you please show me how to do these problems?

1. mols = M x L = ?

Then mols = grams/molar mass. Substitute mols and molar mass and solve for grams.

2. Just like 1 but in reverse.
mols Na2SO4 = grams/molar mass = ?
Then M x L = mols. You know mols and M, solve for L.

3. I think this is just #1 again.
I'll check you answers if you post your work (not just the answers)

Sure! I'd be happy to walk you through each of these problems step by step.

1. How many grams of KCl is in 225 mL of a 0.452 M solution?
To solve this problem, we will need to use the formula: grams = moles × molar mass.

Step 1: Calculate the moles of KCl in the solution.
First, we need to convert the volume (225 mL) to liters by dividing by 1000.
225 mL ÷ 1000 = 0.225 L

Then, use the formula: moles = molarity × volume.
moles = 0.452 M × 0.225 L = 0.1017 moles

Step 2: Calculate the mass of KCl.
Next, we need to find the molar mass of KCl, which is K (39.10 g/mol) + Cl (35.45 g/mol) = 74.55 g/mol.

Finally, use the formula: grams = moles × molar mass.
grams = 0.1017 moles × 74.55 g/mol = 7.57 grams

Therefore, there are approximately 7.57 grams of KCl in 225 mL of the 0.452 M solution.

2. What volume in mL of 0.555 M solution contains 85.0g Na2SO4?
For this problem, we will use the same formula: moles = mass / molar mass.

Step 1: Calculate the moles of Na2SO4.
To do this, we need to find the molar mass of Na2SO4, which is Na (22.99 g/mol) × 2 + S (32.06 g/mol) + O (16.00 g/mol) × 4 = 142.04 g/mol.

Then, use the formula: moles = mass / molar mass.
moles = 85.0 g / 142.04 g/mol = 0.598 moles

Step 2: Calculate the volume of the solution.
We know the molarity of the solution (0.555 M) and the moles of Na2SO4 (0.598 moles).
We can rearrange the formula moles = molarity × volume to solve for volume.
volume = moles / molarity = 0.598 moles / 0.555 M ≈ 1.08 L

Finally, convert the volume from liters to milliliters by multiplying by 1000.
volume = 1.08 L × 1000 mL/L ≈ 1080 mL

Therefore, 85.0 grams of Na2SO4 would be dissolved in approximately 1080 mL of the 0.555 M solution.

3. How many grams of CaCl2 would be dissolved in 2.0L of a 0.10 M solution of CaCl2?
Again, we will use the formula: grams = moles × molar mass.

Step 1: Calculate the moles of CaCl2.
We have the molarity of the solution (0.10 M) and the volume (2.0 L).
Use the formula: moles = molarity × volume.
moles = 0.10 M × 2.0 L = 0.20 moles

Step 2: Calculate the mass of CaCl2.
To find the molar mass of CaCl2, which is Ca (40.08 g/mol) + Cl (35.45 g/mol) × 2 = 110.98 g/mol.

Finally, use the formula: grams = moles × molar mass.
grams = 0.20 moles × 110.98 g/mol = 22.20 grams

Therefore, approximately 22.20 grams of CaCl2 would be dissolved in 2.0 L of the 0.10 M solution.