What is the maximum mass of H2O that can be produced by combining 71.7 g of each reactant?
4NH3 (g) + 5O2 (g) -----> 4NO (g) + 6H2O (g)
___________ g H2O ?
Tim, this is just like the problem you posted below which Jundy answered incorrectly but I followed up. What is it you don't understand about limiting reagent problems? We need to get you so you can work all of these yourself.
To determine the maximum mass of H2O that can be produced, we need to follow the stoichiometry of the balanced chemical equation.
Given:
Reactant 1: 71.7 g of NH3
Reactant 2: 71.7 g of O2
Step 1: Convert the mass of NH3 to moles.
To do this, we need to know the molar mass of NH3, which is:
1 mol NH3 = 17.03 g NH3
Using the given mass of NH3 and the molar mass, we can calculate the number of moles of NH3:
71.7 g NH3 * (1 mol NH3 / 17.03 g NH3) = 4.208 mol NH3
Step 2: Now, let's determine the limiting reactant.
To determine the limiting reactant, we need to compare the moles of both reactants to the stoichiometric ratio in the balanced equation. From the balanced equation:
4 mol NH3 : 5 mol O2
For every 4 moles of NH3, we need 5 moles of O2. Therefore, we can calculate the number of moles of O2 needed:
4.208 mol NH3 * (5 mol O2 / 4 mol NH3) = 5.26 mol O2
Since we have 4.208 moles of NH3 and 5.26 moles of O2, we can see that the O2 is the limiting reactant because we have fewer moles of O2 compared to NH3.
Step 3: Calculate the maximum moles of H2O produced.
From the balanced equation, we can see that for every 5 moles of O2, we produce 6 moles of H2O.
Since O2 is the limiting reactant, we use the moles of O2 to calculate the moles of H2O:
5.26 mol O2 * (6 mol H2O / 5 mol O2) = 6.314 mol H2O
Step 4: Convert the moles of H2O to grams.
To do this, we need to know the molar mass of H2O, which is:
1 mol H2O = 18.015 g H2O
Using the calculated moles of H2O and the molar mass, we can calculate the mass of H2O:
6.314 mol H2O * (18.015 g H2O / 1 mol H2O) = 113.754 g H2O
Therefore, the maximum mass of H2O that can be produced by combining 71.7 g of each reactant is approximately 113.754 grams.