Calculate the range of the projectile using the initial speed and angle. Use g = 9.8m/s your calculation.
Initial speed is 18m/s
Angle is 75
Help please !!
Range of projectile formula:
R = vo^2 sin(2θ) / g
where
θ = angle
vo - initial velocity
g = acceleration due to gravity = 9.8 m/s^2
substitute the values to get the range:
R = (18^2) * sin(2*75°) / 9.8
R = ?
Make sure your calculator is in Degrees mode, not Radians mode.
Hope this helps~ `u`
To calculate the range of a projectile, we can use the equations of projectile motion. The range is the horizontal distance traveled by the projectile before it lands.
First, we need to break down the initial velocity into its horizontal and vertical components.
The horizontal component (Vx) of the initial velocity can be calculated using the formula Vx = V * cos(A), where V is the initial speed and A is the angle.
Vx = 18 m/s * cos(75°)
Now, let's calculate Vx:
Vx = 18 m/s * cos(75°)
Vx = 18 m/s * 0.2588
Vx = 4.6576 m/s
(rounding to four decimal places)
Next, we can calculate the time of flight (T) using the formula T = 2 * (Vy / g), where Vy is the vertical component of the initial velocity and g is the acceleration due to gravity.
To find Vy, we can use the formula Vy = V * sin(A):
Vy = 18 m/s * sin(75°)
Vy = 18 m/s * 0.9659
Vy = 17.3875 m/s
(rounding to four decimal places)
Now, let's calculate the time of flight:
T = 2 * (Vy / g)
T = 2 * (17.3875 m/s / 9.8 m/s^2)
T = 2 * 1.7717 s
T = 3.5434 s
(rounding to four decimal places)
Finally, we can calculate the range (R) using the formula R = Vx * T:
R = 4.6576 m/s * 3.5434 s
R = 16.4794 m
(rounding to four decimal places)
Therefore, the range of the projectile is approximately 16.4794 meters.