Solve the system by the substitution method. Show your work.
2y - x = 5
x2 + y2 - 25 = 0
2y - x = 5
x = 2y-5
Online "^" is used to indicate an exponent, e.g., x^2 = x squared.
x^2 + y^2 - 25 = 0
Substitute 2y-5 for x in the third equation and solve for y. Insert that value into the second equation to solve for x. Check by putting both values into the third equation.