the base if an isosceles triangle is 4/3cm. the perimeter of the triangle is 4 2/15cm. what is the length of either of the remaining equal sides
2x + 4/3 = 62/15
solve for x
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Class 8th math all n.c.e.r.t book ka solutions
To find the length of either of the remaining equal sides of an isosceles triangle, we need to first calculate the length of the base.
Given that the base of the triangle is 4/3 cm, we know that each of the other two equal sides is also 4/3 cm.
Now, to find the perimeter of the triangle, which is 4 2/15 cm, we add the lengths of all three sides.
Perimeter = Length of Base + 2 * Length of Equal Sides
4 2/15 = 4/3 + 2 * Length of Equal Sides
Next, let's convert the mixed fraction (4 2/15) into an improper fraction.
4 2/15 = 62/15
Now our equation becomes:
62/15 = 4/3 + 2 * Length of Equal Sides
To solve for the length of either of the remaining equal sides, we can isolate the variable.
Subtract 4/3 from both sides:
62/15 - 4/3 = 2 * Length of Equal Sides
To add these fractions, let's find a common denominator. The common denominator for 15 and 3 is 15.
(62 - 20) / 15 = 2 * Length of Equal Sides
42/15 = 2 * Length of Equal Sides
Divide both sides by 2:
(42/15) / 2 = Length of Equal Sides
(14/5) / 2 = Length of Equal Sides
Multiplying by the reciprocal:
(14/5) * (1/2) = Length of Equal Sides
14/10 = Length of Equal Sides
Simplifying the fraction:
7/5 = Length of Equal Sides
Therefore, the length of either of the remaining equal sides of the isosceles triangle is 7/5 cm.