Question

The wind chill factor represents the equivalent air temperature at a standard wind speed that would produce the same heat loss as the given temperature and wind speed. One formula for computing the equivalent temperature is

𝑡
W(t) = {33 − (10.45+10√𝑣−𝑣)(33−𝑡) / 2204
33 − 1.5958(33 − 𝑡)

if 0 ≤ v < 1.79
if 1.79 ≤ v < 20
if v ≥ 20

where v represents the wind speed (in meters per second) and t represents the air temperature . Compute the wind chill for an air temperature of 15°C and a wind speed of 12 meters per second. (Round the answer to one decimal place.) Show your work.

This answer is 6.0 C but I don't know how to put my work together.

Answer 1

better write your function. I can't decipher it. How about

f(v) =
jlkjasklj if 0 <= v < 1.79
ahahhahas if 1.79 <= v < 20
and so on, each section on its own line.

And you can lose those 𝑡 characters, which show up as small boxes on my browser.

Answer 2

[AI-generated answer — Explain Bot]

To compute the wind chill for an air temperature of 15°C and a wind speed of 12 meters per second, you need to substitute the given values into the appropriate formula. Here's how you can work it out:

1. Determine the wind speed category:
Since v = 12 is greater than or equal to 1.79 but less than 20, we will use the second formula.

2. Substitute the values into the formula:
W(t) = {33 − (10.45+10√𝑣−𝑣)(33−𝑡) / 2204
33 − 1.5958(33 − 𝑡)

W(t) = {33 − (10.45+10√12−12)(33−15) / 2204
33 − 1.5958(33 − 15)

3. Simplify the equation:
W(t) = {33 − (10.45+10(3.4641−12))(33−15) / 2204
33 − 1.5958(33 − 15)

W(t) = {33 − (10.45+(-84.359))(33−15) / 2204
33 − 1.5958(33 − 15)

W(t) = {33 − (-73.909))(33−15) / 2204
33 − 1.5958(33 − 15)

W(t) = {33 + 73.909)(33−15) / 2204
33 − 1.5958(33 − 15)

W(t) = (106.909)(33−15) / 2204
33 − 1.5958(33 − 15)

W(t) = (106.909)(18) / 2204
33 − 1.5958(33 − 15)

W(t) = (1923.362) / 2204
33 − 1.5958(33 − 15)

W(t) = 0.8729
33 − 1.5958(33 − 15)

4. Simplify further:
W(t) = 0.8729
33 − 1.5958(33 − 15)

W(t) = 0.8729
33 − 1.5958(18)

W(t) = 0.8729
33 − 28.7244

W(t) = 0.8729
4.2756

W(t) = 0.8729 / 4.2756

W(t) = 0.204

Therefore, the wind chill for an air temperature of 15°C and a wind speed of 12 meters per second is approximately 0.2°C when rounded to one decimal place.