Boris has a coin and a number cube. The number cube is labeled 1-6. He flips the coin once and rolls the number cube once. What is the probability that the coin lands tails up and the cube lands on a even number?
A. 2/3
B. 1/4
C. 1/12
D. 1/6
How do i solve this problem? I'm confused
coin = 1/2
Cube has number 1, 2, 3, 4, 5, and 6
so 2, 4, 6 are even numbers which is 1/2 of the cube
So 1/2*1/2 = 1/4
peyton that asnwer isnt even there bruhhh
Well, solving probability problems can be quite the gamble! But fear not, I'm here to help you out and hopefully make you laugh along the way.
Now, we first need to determine the possible outcomes of flipping a coin and rolling a number cube. Since we're only interested in the probability of getting tails up on the coin and landing on an even number on the cube, let's see what we've got:
For the coin, there are two possible outcomes: heads or tails. So, the probability of getting tails up is 1/2.
For the number cube, there are six possible outcomes: 1, 2, 3, 4, 5, or 6. Out of these, three of them are even numbers: 2, 4, and 6. This means the probability of landing on an even number is 3/6, which simplifies to 1/2.
Now, to find the probability of both events occurring together, we need to multiply the individual probabilities. So, the probability of getting both tails up on the coin and an even number on the cube is (1/2) * (1/2) = 1/4.
So, my friend, the correct answer is B. 1/4. Good luck with your probability adventures!
To solve this problem, you need to find the probability of the coin landing tails up and the number cube landing on an even number.
Step 1: Determine the possible outcomes. The coin has two possible outcomes: heads or tails. The number cube has six possible outcomes: 1, 2, 3, 4, 5, or 6.
Step 2: Determine the favorable outcomes. In this case, we want the coin to land tails up (1 outcome) and the number cube to land on an even number (3 outcomes: 2, 4, or 6).
Step 3: Calculate the probability. The probability is given by the formula: favorable outcomes / total outcomes. In this case, the favorable outcomes are 1 (tails up) x 3 (even numbers on the cube). The total outcomes are 2 (coin) x 6 (number cube). Therefore, the probability is (1 x 3) / (2 x 6) = 3 / 12 = 1 / 4.
So, the correct answer is option B. The probability that the coin lands tails up and the cube lands on an even number is 1/4.