If a tank contains water 4 m deep, what is the pressure at the bottom of the tank? (Neglect the atmospheric pressure.)
A. 39.2 kPA
B. 18.9 kPA
C. 4.0 kPa
D. 9.8 kPA
Im really lost
pressure=density*g*height.
~1000*9.8*4=39200 Pa, 39.2kPa
Oh My God, thank you so much
To find the pressure at the bottom of a tank of water, you can use the concept of hydrostatic pressure. Hydrostatic pressure is the pressure exerted by a fluid at equilibrium due to the force of gravity acting on the fluid. The formula for calculating hydrostatic pressure is:
P = ρgh
Where:
P is the pressure
ρ (rho) is the density of the fluid
g is the acceleration due to gravity
h is the height or depth of the fluid
In this case, we are given that the tank contains water, so we can assume the density of water is 1000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². And the depth of the water is given as 4 meters.
Plugging these values into the formula, we get:
P = (1000 kg/m³)(9.8 m/s²)(4 m)
P = 39,200 N/m²
Now we need to convert this pressure from Newtons per square meter (N/m²) to kilopascals (kPa). Since 1 N/m² is equal to 1 Pascal (Pa), and 1 kPa is equal to 1000 Pa, we divide the pressure by 1000 to convert it to kPa:
39,200 N/m² / 1000 = 39.2 kPa
Therefore, the correct answer is A. 39.2 kPa.