What is the equation of the line that passes through (-6,-2) and is parallel it the line with the equation x=4
x=4 gives inclination=k=1 in y=kx+m. It also states that m=4.
y=x+4
Better think again, S.
the line x=4 is a vertical line
The vertical line through (-6,-2) is x = -6
To find the equation of a line parallel to x=4 and passing through the point (-6,-2), we need to find the equation in slope-intercept form (y=mx+b) because the given form is not suitable for this purpose.
Step 1: Determine the slope of the line x=4.
Since the line is vertical (parallel to the y-axis) and x remains constant at 4, the slope is undefined.
Step 2: Find the slope of the line we want to determine by using the fact that parallel lines have the same slope.
Since the given line has an undefined slope, our desired line will also have an undefined slope.
Step 3: Determine the equation of the line using the point-slope form (y - y1 = m(x - x1)).
Since the slope is undefined, the equation becomes x = x1, where x1 is the x-coordinate of any point on the line.
In this case, the point (-6,-2) lies on the line we want to find.
Therefore, the equation is x = -6.
So, the equation of the line parallel to x=4 and passing through the point (-6,-2) is x = -6.