What are the correct and accurate products for the following ion combination reaction? Then write the ionic form of the reaction and the net ionic form of the reaction.
K2CO3 + CaCl2 ->
See your H2SO4 + KOH problem below. It's the same process.
Ca2+ + CO3(2+) = CaCO3 (sediment)
To determine the correct and accurate products for the given ion combination reaction, we need to understand the charges and valence of each ion involved.
The ions involved in the reaction are:
1. K2CO3: This compound consists of potassium ions (K+) and carbonate ions (CO3^2-).
2. CaCl2: This compound consists of calcium ions (Ca^2+) and chloride ions (Cl-).
First, we need to recognize that this is a double replacement reaction, where the positive ions from each compound will switch places.
To determine the products, we pair the positive ions of each compound with the negative ions of the other compound. So, the products can be predicted as follows:
K2CO3 + CaCl2 -> KCl + CaCO3
The ionic form of the reaction represents all the ions involved in the reaction and their respective charges. The ionic form of this reaction is:
2K+ + CO3^2- + Ca^2+ + 2Cl- -> 2K+ + 2Cl- + CaCO3
In the net ionic form of the reaction, we eliminate the spectator ions, which are the ions that appear on both sides of the equation without undergoing any change. In this case, the spectator ions are the two K+ and two Cl- ions. Thus, the net ionic form of the reaction is:
CO3^2- + Ca^2+ -> CaCO3
Note that in the net ionic form, we only include the ions that are directly involved in the reaction and have undergone a change.