Anna applies a force of 19.5 newtons to push a book placed on a table. If the normal force of the book is 51.7 newtons, what is the coefficient of kinetic friction?

A) .01
B) .20
C) .38
D) .48

So if you divide 19.5 / 51.7 the answer is .38 so C is the answer.

normal force * coefficent=friction

solve for coefficient

In this case friction 19.5
Normal force is 51.7N

so whats the answer....

this answer sucks

To determine the coefficient of kinetic friction, we can use the equation:

\(f_k = \mu_k \cdot N\)

Where:
\(f_k\) is the force of kinetic friction,
\(\mu_k\) is the coefficient of kinetic friction,
and \(N\) is the normal force.

In this case, Anna applies a force of 19.5 newtons, and the normal force of the book is 51.7 newtons. We need to find the coefficient of kinetic friction.

Rearranging the equation, we can solve for \(\mu_k\):

\(\mu_k = \frac{f_k}{N}\)

Plugging in the given values, we have:

\(\mu_k = \frac{19.5}{51.7}\)

Now, let's calculate the coefficient of kinetic friction:

\(\mu_k \approx 0.3777\)

The closest option to 0.3777 is 0.38, so the correct answer is option C) .38.

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