A 25.00 mL sample of HCl was titrated with 35.79 mL of 0.250 M KOH. The concentration of the HCl solution is:
volumebase*Normalitybase=volumeacid*Normalityacid
35.79*.250=25*x
x=35.79/100=.3579 M
the answer is ######
To find the concentration of the HCl solution, we can use the formula of the balanced chemical equation for the reaction between HCl and KOH:
HCl + KOH -> H2O + KCl
From the balanced equation, we can see that the mole ratio between HCl and KOH is 1:1. This means that the number of moles of HCl is equal to the number of moles of KOH used in the titration.
We know the volume and concentration of KOH used in the titration:
Volume of KOH = 35.79 mL
Concentration of KOH = 0.250 M
First, we need to find the number of moles of KOH used in the titration:
Moles of KOH = Volume of KOH x Concentration of KOH
= 35.79 mL x 0.250 M
= 8.9475 mmol (millimoles)
Since the reaction is 1:1, the number of moles of HCl is also 8.9475 mmol.
Next, we need to convert the volume of the HCl solution to liters:
Volume of HCl = 25.00 mL
= 25.00 mL / 1000 mL/L
= 0.02500 L
Now, we can calculate the concentration of the HCl solution:
Concentration of HCl = Moles of HCl / Volume of HCl
= 8.9475 mmol / 0.02500 L
= 357.9 mmol/L
Finally, we convert the concentration to Molarity (M) by dividing by 1000:
Concentration of HCl = 357.9 mmol/L / 1000
= 0.3579 M
Therefore, the concentration of the HCl solution is 0.3579 M.
To find the concentration of the HCl solution, you can use the concept of stoichiometry and the balanced chemical equation for the reaction between HCl and KOH.
The balanced chemical equation for the reaction between HCl and KOH is:
HCl + KOH → H2O + KCl
From the balanced equation, we can see that the stoichiometric ratio between HCl and KOH is 1:1. This means that for every 1 mole of HCl, we need 1 mole of KOH to react completely.
First, let's determine the number of moles of KOH used in the reaction:
moles of KOH = volume of KOH solution (in L) × molarity of KOH solution
Given:
volume of KOH solution = 35.79 mL = 35.79/1000 L = 0.03579 L
molarity of KOH solution = 0.250 M
moles of KOH = 0.03579 L × 0.250 M = 0.0089475 mol
Since the stoichiometric ratio is 1:1, the number of moles of HCl used in the reaction is also 0.0089475 mol.
Now, let's find the concentration of the HCl solution:
concentration of HCl solution = moles of HCl / volume of HCl solution (in L)
Given:
volume of HCl solution = 25.00 mL = 25.00/1000 L = 0.02500 L
concentration of HCl solution = 0.0089475 mol / 0.02500 L = 0.3579 M
Therefore, the concentration of the HCl solution is 0.3579 M.