calculate the force of gravity between a newborn baby of mass 2.9kg and the obstertrician of mass 100kg, who is 0.48m from the baby.

To calculate the force of gravity between the newborn baby and the obstetrician, we can use Newton's law of universal gravitation.

The formula for calculating the force of gravity (F) between two objects is:

F = (G * m1 * m2) / r^2

Where:
F is the force of gravity
G is the gravitational constant (approximately 6.67430 x 10^-11 N*m^2/kg^2)
m1 and m2 are the masses of the two objects
r is the distance between the centers of the two objects

Let's plug in the values given in the question:

m1 = mass of the baby = 2.9 kg
m2 = mass of the obstetrician = 100 kg
r = distance between the baby and the obstetrician = 0.48 m

Using the formula, we can calculate the force of gravity (F):

F = (6.67430 x 10^-11 N*m^2/kg^2 * 2.9 kg * 100 kg) / (0.48 m)^2

Now we can compute the force:

F = (6.67430 x 10^-11 * 2.9 * 100) / (0.48)^2

F = (1.934707 x 10^-8) / 0.2304

F ≈ 8.398371 x 10^-8 N

Therefore, the force of gravity between the newborn baby and the obstetrician is approximately 8.398371 x 10^-8 Newtons.

To calculate the force of gravity between two objects, we can use Newton's law of universal gravitation:

F = (G * m1 * m2) / r^2

Where:
F is the force of gravity
G is the gravitational constant (approximately 6.674 × 10^-11 Nm^2/kg^2)
m1 and m2 are the masses of the objects
r is the distance between the centers of the objects

In this case, the mass of the newborn baby is 2.9kg (m1) and the mass of the obstetrician is 100kg (m2). The distance between them is 0.48m (r). Let's plug these values into the equation and calculate the force of gravity:

F = (6.674 × 10^-11 Nm^2/kg^2 * 2.9kg * 100kg) / (0.48m)^2

Simplifying the equation:

F = (6.674 × 10^-11 Nm^2/kg^2 * 290kg) / (0.48m)^2
F = (6.674 × 10^-11 Nm^2/kg^2 * 290kg) / 0.23m^2
F = (1.93586 × 10^-8 Nm^2/kg^2) / 0.053676m^2

Calculating the final value:

F = 3.6076 × 10^-7 N

Therefore, the force of gravity between the newborn baby and the obstetrician is approximately 3.6076 × 10^-7 Newtons.