How do i solve for x (x^2-9)(2x+1)=0
lucky for you, the equation is already partially factored, just one more step
(x+3)(x-3)(2x+1) = 0
set each factor equal to zero, and solve for x
thanks a lot can you give me your email reiny
To solve the equation (x^2-9)(2x+1) = 0, you can use the zero product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero.
In this equation, you have two factors: (x^2-9) and (2x+1).
To solve for x, you set each factor equal to zero and solve for x separately.
1. Setting the first factor equal to zero:
(x^2-9) = 0
To solve this equation, we can factor the difference of squares formula: (a^2 - b^2) = (a + b)(a - b).
(x+3)(x-3) = 0
Now, we have two separate equations to solve:
a) x+3 = 0
x = -3
b) x-3 = 0
x = 3
So, the solutions for the first factor are x = -3 and x = 3.
2. Setting the second factor equal to zero:
(2x+1) = 0
To isolate x, we need to move 1 to the other side of the equation:
2x = -1
Now, divide both sides by 2:
x = -1/2
So, the solution for the second factor is x = -1/2.
Therefore, the solutions for the original equation (x^2-9)(2x+1) = 0 are x = -3, x = 3, and x = -1/2.