Propane fuel is used in BBQs. Use the following reaction to determine how many moles of oxygen gas are needed to react with 1.6 moles of propane gas.
C3H8(g)+5O2(g) --------> 4H2O(g)+ 3CO2(g)
To determine how many moles of oxygen gas (O2) are needed to react with 1.6 moles of propane gas (C3H8), you need to use the balanced equation provided.
According to the balanced equation:
C3H8(g) + 5O2(g) → 4H2O(g) + 3CO2(g)
The ratio between propane gas and oxygen gas is 1:5. This means that for every 1 mole of propane gas, you will need 5 moles of oxygen gas.
Given that you have 1.6 moles of propane gas, you can calculate the moles of oxygen gas needed as follows:
1.6 moles propane gas × (5 moles oxygen gas / 1 mole propane gas) = 8 moles oxygen gas
Therefore, you will need 8 moles of oxygen gas to react with 1.6 moles of propane gas.
To determine how many moles of oxygen gas (O2) are needed to react with 1.6 moles of propane gas (C3H8), we can use the balanced equation for the reaction:
C3H8(g) + 5O2(g) → 4H2O(g) + 3CO2(g)
From the balanced equation, we can see that for every 1 mole of propane gas (C3H8), 5 moles of oxygen gas (O2) are required.
So, if we have 1.6 moles of propane gas, we can set up a proportion to find the number of moles of oxygen gas needed:
1.6 moles C3H8 / 1 mole C3H8 = x moles O2 / 5 moles O2
Using the proportion, we can solve for x:
x = (1.6 moles C3H8 * 5 moles O2) / 1 mole C3H8
x = 8 moles O2
Therefore, 8 moles of oxygen gas are needed to react with 1.6 moles of propane gas.