calculate the molarity of cl- ions in a solution made from mixing 50.0 ml of a 0.100 m/l solution of ferric chloride with 50.0 ml of a 0.500 mol/l solution of ammonium chloride
find the moles of each element then divided by total volume
To calculate the molarity of Cl- ions in the solution, you need to determine the number of moles of Cl- ions present and then divide by the total volume of the solution. Here's how you can do it step by step:
1. Start by calculating the number of moles of Cl- ions in each solution.
- For the ferric chloride solution (0.100 mol/L), the concentration is given. Multiply this by the volume (50.0 mL or 0.050 L) to get moles:
0.100 mol/L x 0.050 L = 0.005 mol of Cl- ions
- For the ammonium chloride solution (0.500 mol/L), again multiply the concentration by the volume (50.0 mL or 0.050 L):
0.500 mol/L x 0.050 L = 0.025 mol of Cl- ions
2. Now, add the moles of Cl- ions from both solutions to get the total number of moles:
0.005 mol + 0.025 mol = 0.030 mol
3. Next, calculate the total volume of the solution. Since you mixed equal volumes of both solutions (50.0 mL each), the total volume is 100.0 mL or 0.100 L.
4. Finally, divide the total moles of Cl- ions by the total volume of the solution to get the molarity of Cl- ions:
Molarity = Moles of Cl- ions / Volume of solution
Molarity = 0.030 mol / 0.100 L = 0.300 mol/L
Therefore, the molarity of Cl- ions in the solution is 0.300 mol/L.