What is the formula for the following problem

What is the kinetic energy, in joules of a mole of oxygen moving at a speed of 225m s ⁻1?

Should I use KE= 1/2mv2

Thanks

Yes, you are correct. To calculate the kinetic energy (KE) of an object, you can use the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.

In this case, you are trying to find the kinetic energy of a mole of oxygen moving at a speed of 225 m/s. To use the formula, you will need to know the mass of a mole of oxygen.

The molar mass of oxygen (O₂) is approximately 32 g/mol. However, in order to use the mass in the formula, it needs to be converted to kilograms.

To convert grams to kilograms, you divide by 1000. So the mass of a mole of oxygen (in kilograms) is 32 g / 1000 = 0.032 kg.

Now that you have the mass (m = 0.032 kg) and velocity (v = 225 m/s), you can substitute these values into the formula:

KE = 1/2 * m * v^2

KE = 1/2 * 0.032 kg * (225 m/s)^2

KE ≈ 0.288J

Therefore, the kinetic energy of a mole of oxygen moving at a speed of 225 m/s is approximately 0.288 Joules.