An equilibrium mixture of N2, H2, and NH3 at 700 K contains 0.031 M N2 and 0.52 M H2. At this temperature, Kc for the reaction is 0.29. What is the concentration of NH3?

N2(g) + 3H2(g) (equilibrium arrow) 2NH3(g)

To calculate the concentration of NH3, we can use the equation for the equilibrium constant (Kc) and the initial concentrations of N2 and H2:

Kc = [NH3]^2 / ([N2] * [H2]^3)

Given:
[N2] = 0.031 M (concentration of N2)
[H2] = 0.52 M (concentration of H2)
Kc = 0.29 (equilibrium constant)

We can substitute these values into the equation to find the concentration of NH3:

0.29 = [NH3]^2 / (0.031 * 0.52^3)

To find [NH3], we multiply both sides of the equation by (0.031 * 0.52^3):

0.29 * (0.031 * 0.52^3) = [NH3]^2

Now, take the square root of both sides of the equation to solve for [NH3]:

[NH3] = √(0.29 * 0.031 * 0.52^3)

Using a calculator, we find that [NH3] ≈ 0.012 M (approximately).

Therefore, the concentration of NH3 in the equilibrium mixture is approximately 0.012 M.

Set up K expression, substitute the equilibrium mixture of N2 and H2 and solve for NH3.