A mother rocket fired from the ground last year’s eve ejects 25% of its mass at the at the rate if so m/s in the first second of its flight. Find the initial acceleration of the mother rocket.

To find the initial acceleration of the mother rocket, we first need to understand the concept of momentum and Newton's second law of motion.

Newton's second law of motion states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. Mathematically, it can be expressed as:

F = m * a

Where:
F is the net force acting on the object,
m is the mass of the object, and
a is the acceleration of the object.

In this case, we know that the mother rocket ejects 25% of its mass at a specific rate. Let's assume the total mass of the rocket is m0, and the mass ejected in the first second is m1 (25% of the total mass).

m1 = 0.25 * m0

The net force acting on the rocket is equal to the rate of change of momentum. The momentum of an object is given by the product of its mass and its velocity:

p = m * v

The rate of change of momentum can be calculated using the equation:

F = Δp / Δt

Where:
Δp is the change in momentum,
Δt is the change in time, and
F is the net force acting on the object.

In this case, we can calculate the acceleration using the following equation:

F = m1 * Δv / Δt

Now, we know from the problem statement that the rate at which the mass is ejected is given as "s m/s." Let's assume the velocity of ejection is v.

v = s m/s

Now, we can substitute the values into the equation for acceleration:

a = (m1 * v) / Δt

But we need to find Δt, the change in time. Since the problem states that only the first second of flight is considered, we can set Δt = 1s.

Substituting the known values, we have:

a = (m1 * v) / 1

Since the problem doesn't provide specific values for m1 and v, we cannot calculate the exact value of the initial acceleration without this information. However, using this formula, you can plug in the specific values provided in the problem to find the answer.