Harold has a photograph that is 8 in. Test Image 10 in. that he wants to print at a reduced size to fit into a frame that is 6 in. tall. What will be the dimensions of the new photograph?

To calculate the dimensions of the new photograph, we can consider the aspect ratio of the original and the desired height of the new photograph.

The aspect ratio of the original photograph is 8:10, which can be simplified to 4:5.

Let's assume the width of the new photograph is "x" inches.

According to the aspect ratio, the height of the new photograph will be (4/5) * x inches.

Given that the height of the new photograph should be 6 inches, we can set up the following equation:

(4/5) * x = 6

To solve for "x," we can multiply both sides of the equation by (5/4):

x = (6 * 5) / 4

x = 7.5

Therefore, the width of the new photograph will be 7.5 inches.

Hence, the dimensions of the new photograph will be 7.5 in x 6 in.

To find the dimensions of the new photograph, we need to maintain the original proportions of the photograph while reducing its size to fit the frame.

Let's start by finding the proportion between the original photograph and the frame. We divide the height of the frame (6 in) by the height of the original photograph (10 in):

Proportion = Frame height / Original photograph height
= 6 in / 10 in
= 0.6

This proportion represents how much we need to reduce the size of the original photograph. To find the new dimensions, we will apply this proportion to both the height and width of the original photograph.

New photograph height = Original photograph height × Proportion
= 10 in × 0.6
= 6 in

New photograph width = Original photograph width × Proportion
= 8 in × 0.6
= 4.8 in

Therefore, the new dimensions of the photograph will be 6 inches in height and 4.8 inches in width.

No idea what your garbled text means, but if the image is 10" tall, and must fit into a 6" frame, then it must be reduced by at least a factor of 6/10.

Same for the width. So, since 8 * 6/10 = 4.8, the reduced picture needs to be 4.8 x 6