Determine the number of molecules of the compound iron phosphate with 129.68 g Fe3(PO4)2

Is that ferrous phosphate; aka, iron(II) phosphate?

mols Fe3(PO4)2 = grams/molar mass = ?
# molecules = mols x 6.02E23 = ?

To determine the number of molecules of iron phosphate (Fe3(PO4)2) with a mass of 129.68 g, you can follow these steps:

Step 1: Determine the molar mass of Fe3(PO4)2.
The molar mass of iron (Fe) is 55.845 g/mol.
The molar mass of phosphate (PO4) is 94.9714 g/mol.
Fe3(PO4)2 contains 3 iron atoms and 2 phosphate groups.
So, the molar mass of Fe3(PO4)2 can be calculated as:
Molar mass = (3 x Fe) + (2 x PO4)
Molar mass = (3 x 55.845 g/mol) + (2 x 94.9714 g/mol)
Molar mass = 167.535 g/mol + 189.9428 g/mol
Molar mass = 357.4778 g/mol

Step 2: Calculate the number of moles of Fe3(PO4)2.
Number of moles = Mass of the compound / Molar mass
Number of moles = 129.68 g / 357.4778 g/mol
Number of moles ≈ 0.3624 mol

Step 3: Use Avogadro's number to determine the number of molecules.
Avogadro's number is 6.022 × 10^23 molecules/mol.
Number of molecules = Number of moles x Avogadro's number
Number of molecules = 0.3624 mol x 6.022 × 10^23 molecules/mol

By performing the calculation, the number of molecules of Fe3(PO4)2 with a mass of 129.68 g is approximately 2.18 x 10^23 molecules.

To determine the number of molecules in a compound, you need to use the concept of Avogadro's number and the molar mass of the compound.

Step 1: Calculate the molar mass of Fe3(PO4)2.

Fe3(PO4)2 consists of three iron atoms (Fe), two phosphate groups (PO4), and two phosphate ions.

The molar mass of Fe is 55.85 g/mol, and the molar mass of PO4 is 94.97 g/mol.
So, the molar mass of Fe3(PO4)2 can be calculated as follows:

Molar mass of Fe3(PO4)2 = (3 * molar mass of Fe) + (2 * molar mass of PO4)
= (3 * 55.85 g/mol) + (2 * 94.97 g/mol)
= 167.55 g/mol + 189.94 g/mol
= 357.49 g/mol

Step 2: Calculate the number of moles of Fe3(PO4)2.

To do this, divide the given mass of Fe3(PO4)2 by its molar mass:

Number of moles = mass / molar mass
= 129.68 g / 357.49 g/mol
≈ 0.362 moles

Step 3: Use Avogadro's number to determine the number of molecules.

Avogadro's number, denoted by Nᴀ, is defined as 6.022 × 10^23 molecules per mole.

Number of molecules = number of moles × Avogadro's number
= 0.362 moles × 6.022 × 10^23 molecules/mol
≈ 2.18 × 10^23 molecules

Therefore, the number of molecules in 129.68 g of Fe3(PO4)2 is approximately 2.18 × 10^23 molecules.