Pydrotinces comes in 50 mg/mL. A child is to get 2 mg. The volume in a miniscule of 0.04mL, which is really had to measure. Prepare a dilution so that final concentration is 5mg/mL. How much diluent well you need is the original products is 50mg/mL and you dilute the entire vial? what is the volume of the final bills to be measured?
Hydrocortisone comes in 50 mg/mL. A child is to get 2 mg. The volume in a miniscule of 0.04mL, which is really had to measure. Prepare a dilution so that final concentration is 5mg/mL. How much diluent well you need is the original products is 50mg/mL and you dilute the entire vial? what is the volume of the final bills to be measured?
first, there is no such word as miniscule. It is minuscule, and it is an adjective, not a noun. I have no idea which word you intended.
you want to reduce the concentration by a factor of 10, so you need to increase the volume by a factor of 10.
Since the original volume is .04mL, you will need to have 0.4mL, or an increase of 0.36mL
So, since 2mg is 1/25 of the entire 50mg, ...
To prepare a dilution with a final concentration of 5mg/mL from a stock solution of 50mg/mL, you can use the dilution formula: C1V1 = C2V2
Where:
C1 = Concentration of the stock solution (50mg/mL)
V1 = Volume of the stock solution to be diluted (unknown)
C2 = Desired final concentration (5mg/mL)
V2 = Final volume of the diluted solution (unknown)
First, solving for V1 by rearranging the formula:
V1 = (C2 * V2) / C1
Substituting the known values:
V1 = (5mg/mL * V2) / 50mg/mL
Now, calculating the volume of the stock solution that needs to be diluted, let's assume we dilute the entire vial (the entire stock solution):
V1 = (5mg/mL * V2) / 50mg/mL
V1 = (5 * V2) / 50
V1 = V2 / 10
Since V1 represents the volume of the stock solution, and we need to determine how much diluent (usually a solvent like water) is needed, we can subtract V1 from V2 to find the volume of the diluent:
Volume of Diluent = V2 - V1
Volume of Diluent = V2 - (V2 / 10)
Volume of Diluent = V2 * (1 - 1/10)
Volume of Diluent = V2 * 9/10
Now, let's calculate the volume of the final solution that needs to be measured. This will be V2:
V2 = Volume of Diluent + V1
V2 = (V2 * 9/10) + V2/10
V2 = (V2 * 9 + V2) / 10
V2 = (10V2 + V2) / 10
V2 = 11V2 / 10
10V2 = 11V2
V2 = 0
It seems there is an error in the calculations, as V2 equals 0. Let's review the problem and attempt the calculations again.
Given:
Stock concentration (C1) = 50mg/mL
Desired final concentration (C2) = 5mg/mL
Let's assume we want to prepare a total volume (V2) of 10 mL for the diluted solution.
Using the dilution formula, C1V1 = C2V2, we can solve for V1:
V1 = (C2 * V2) / C1
V1 = (5mg/mL * 10 mL) / 50mg/mL
V1 = 1 mL
Therefore, 1 mL of the stock solution (50mg/mL) needs to be diluted with 9 mL of diluent (usually water or another suitable solvent) to achieve a final volume of 10 mL and a final concentration of 5mg/mL.
In summary, to prepare the dilution:
- Take 1 mL of the stock solution (50mg/mL)
- Add 9 mL of diluent
- Mix thoroughly to obtain a final volume of 10 mL with a final concentration of 5mg/mL
The volume of the final solution to be measured is 10 mL.