a car goes over a circular hill of 50m radius at a constant speed of 20m/sec . What is the force of the car on the 600N driver at the top of the hill.?

what is 600N-600/g*20^2/50 ?

mg-mv^2/r

Yeah I got 600- 61.2(40)/50 =551.64. I do not know if that is right .

To calculate the force exerted by the car on the driver at the top of the hill, we need to consider the centripetal force acting on the car.

The centripetal force (Fc) is given by the formula:

Fc = (m * v^2) / r

Where:
- Fc is the centripetal force
- m is the mass of the car (driver is not relevant here)
- v is the speed of the car
- r is the radius of the circular path

Given:
- Radius (r) = 50m
- Speed (v) = 20m/s

Since the question does not provide the mass of the car, we cannot calculate the exact force exerted on the driver. However, we can provide the formula to calculate it once the mass is known.

Once the mass of the car is known, substitute the values into the formula and calculate the centripetal force.