Calculate the relative atomic mass of
Limestone CaCo3
Methanol CH3oH
Sulphric acid Ca(No3)2.
(Ca=40.1,C=12,O=16,H=1,S=32).
To calculate the relative atomic mass of a compound, you need to consider the atomic masses of each element present in the compound. The relative atomic mass is the weighted average of the atomic masses.
Let's calculate the relative atomic mass of each compound:
1. Limestone (CaCO3):
The formula for limestone is CaCO3. It consists of one calcium atom (Ca), one carbon atom (C), and three oxygen atoms (O).
Relative atomic mass = (atomic mass of Ca × number of Ca atoms) + (atomic mass of C × number of C atoms) + (atomic mass of O × number of O atoms)
Relative atomic mass = (40.1 × 1) + (12 × 1) + (16 × 3) = 40.1 + 12 + 48 = 100.1
Therefore, the relative atomic mass of limestone (CaCO3) is 100.1.
2. Methanol (CH3OH):
The formula for methanol is CH3OH. It consists of one carbon atom (C), four hydrogen atoms (H), and one oxygen atom (O).
Relative atomic mass = (atomic mass of C × number of C atoms) + (atomic mass of H × number of H atoms) + (atomic mass of O × number of O atoms)
Relative atomic mass = (12 × 1) + (1 × 4) + (16 × 1) = 12 + 4 + 16 = 32
Therefore, the relative atomic mass of methanol (CH3OH) is 32.
3. Sulphuric acid (Ca(NO3)2):
The formula for sulfuric acid is Ca(NO3)2. It consists of one calcium atom (Ca), two nitrogen atoms (N), and six oxygen atoms (O).
Relative atomic mass = (atomic mass of Ca × number of Ca atoms) + (atomic mass of N × number of N atoms) + (atomic mass of O × number of O atoms)
Relative atomic mass = (40.1 × 1) + [(14 × 2) + (16 × 3)] + (16 × 6) = 40.1 + 46 + 96 = 182.1
Therefore, the relative atomic mass of sulfuric acid (Ca(NO3)2) is 182.1.
Please note that the atomic masses provided (Ca=40.1, C=12, O=16, H=1, S=32) are rounded values. The actual atomic masses may have more decimal places, but for these calculations, the given values are sufficient.