what is the iobic equation of zinc +iron(ll)sulphate solution
i mean ionic
Ionic?
Zn + Fe+2 + SO4-2>ZnSO4 + Fe(e)
To determine the ionic equation for the reaction between zinc and iron(II) sulfate, we first need to write out the balanced chemical equation for the reaction:
Zn(s) + FeSO4(aq) → ZnSO4(aq) + Fe(s)
In this reaction, zinc (Zn) reacts with iron(II) sulfate (FeSO4) to form zinc sulfate (ZnSO4) and solid iron (Fe).
Now, let's break down the equation to write the ionic equation. Start by writing the chemical formulas of the compounds as their respective ions:
Zn(s) + Fe2+(aq) + SO4 2-(aq) → Zn2+(aq) + SO4 2-(aq) + Fe(s)
Next, eliminate the spectator ions, which are ions that appear unchanged on both sides of the equation. In this case, the sulfate ions (SO4 2-) are present on both sides, so they can be removed:
Zn(s) + Fe2+(aq) → Zn2+(aq) + Fe(s)
This is the ionic equation for the reaction between zinc and iron(II) sulfate solution. It represents the substances that actually participate in the chemical reaction, without including the spectator ions.