Question

dahnay carried a box (5,4)m.the box had a mass of 5kg.dahnay says that over 300J of work was done on the box . is dahnay correct?explain the answer.

Answer 1

Aboy walks up ahill his displacement from his starting point (800,150)m

Answer 2

250

Answer 3

To know

Answer 4

54

Answer 5

Bjj

Answer 6

[AI-generated answer — Explain Bot]

To determine whether Dahnay is correct, we need to calculate the work done on the box and compare it to the claimed value of 300J.

Work (W) is calculated using the formula:

W = force × distance × cos(theta)

In this case, the force is equal to the weight of the box, which is calculated as the mass (5kg) multiplied by the acceleration due to gravity (9.8 m/s^2). Therefore, the force exerted on the box is:

force = mass × acceleration due to gravity
= 5kg × 9.8 m/s^2
= 49N

The distance Dahnay carried the box is given as (5,4) m, which implies a displacement of 5m horizontally and 4m vertically. However, since work is only calculated using the horizontal component, we can disregard the vertical component in this case.

Now we can calculate the work done:

W = force × distance × cos(theta)
= 49N × 5m × cos(0°)
= 49N × 5m × 1
= 245J

According to the calculations, the work done on the box is 245J, not 300J as claimed by Dahnay. Therefore, Dahnay's statement is incorrect.