When a football is kicked into the air, it has a velocity of 32m/s at an angle of 25º. At the very top of the ball’s path, what is it's vertical velocity?

The vertical component of velocity is

zero.

To find the vertical velocity at the top of the ball's path, we need to decompose the initial velocity into its vertical and horizontal components. The vertical component of the velocity can be found using trigonometry.

The initial velocity of the ball is given as 32 m/s at an angle of 25º. Let’s call the vertical component Vv and the horizontal component Vh.

To find Vv, we can use the formula: Vv = V * sin(θ)

Where:
- Vv is the vertical component of velocity
- V is the initial velocity
- θ is the angle of the velocity vector

Plugging in the values, we get:
Vv = 32 m/s * sin(25º)

So, the vertical component of the initial velocity is:
Vv = 32 m/s * 0.4226
Vv ≈ 13.5216 m/s

Therefore, at the very top of the ball's path, its vertical velocity is approximately 13.52 m/s.