An aqueous solution contains 64g of ethanol( C2H5OH) in 122 grams of solution. The mole fraction of ethanol is:
Find the moles of ethanol and the moles of the solution, and divide ethanol by the solution.
thank you
To find the mole fraction of ethanol in the solution, we need to first calculate the moles of ethanol and the total moles of the solution.
Step 1: Calculate the moles of ethanol (C2H5OH):
The molar mass of ethanol (C2H5OH) can be calculated by adding the atomic masses of each element.
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of ethanol (C2H5OH) = (2 * Molar mass of C) + (6 * Molar mass of H) + Molar mass of O
= (2 * 12.01 g/mol) + (6 * 1.01 g/mol) + 16.00 g/mol
= 46.07 g/mol
Now, we can calculate the moles of ethanol:
Moles of ethanol = Mass of ethanol / Molar mass of ethanol
= 64 g / 46.07 g/mol
≈ 1.389 mol (rounded to three decimal places)
Step 2: Calculate the total moles of the solution:
To find the total moles of the solution, we need to convert the mass of the solution to moles. Since the solution is aqueous, it means water is the solvent.
The molar mass of water (H2O) is 18.02 g/mol.
Moles of water = Mass of water / Molar mass of water
Mass of water = Mass of solution - Mass of ethanol
= 122 g - 64 g
= 58 g
Moles of water = 58 g / 18.02 g/mol
≈ 3.218 mol (rounded to three decimal places)
Therefore, the total moles of the solution = Moles of ethanol + Moles of water
= 1.389 mol + 3.218 mol
≈ 4.607 mol (rounded to three decimal places)
Step 3: Calculate the mole fraction of ethanol:
Mole fraction of ethanol = Moles of ethanol / Total moles of the solution
= 1.389 mol / 4.607 mol
≈ 0.301 (rounded to three decimal places)
So, the mole fraction of ethanol in the aqueous solution is approximately 0.301.