a solid weighs 100g in air 75 g in water and 70 g in oil.find relative density of oil

1.2

Density of the/ density of water=weight in air-weight in oil/weight in air-weight in water=100-70/100-75=30/25=6/5=1.2

Pls give a clear solution

To find the relative density of the oil, we need to compare its density to the density of water. The relative density (also known as specific gravity) is the ratio of the density of the substance to the density of water.

Since the solid weighs 75g in water and 100g in air, we can conclude that its weight loss in water is due to the buoyant force acting on it. This buoyant force is equal to the weight of the volume of water displaced by the solid.

By using Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced, we can determine the volume of the solid.

Volume of the solid = Weight of the solid in air - Weight of the solid in water

Volume of the solid = 100g - 75g = 25g

Now, to find the density of the solid, we divide its mass by its volume:

Density of the solid = Mass of the solid / Volume of the solid

Density of the solid = 100g / 25g = 4 g/cm^3

Next, we can find the density of the oil by using a similar approach. The solid weighs 70g in oil, so once again, we subtract the weight loss in oil from the weight of the solid in air:

Volume of the solid = Weight of the solid in air - Weight of the solid in oil

Volume of the solid = 100g - 70g = 30g

Density of the oil = Mass of the solid / Volume of the solid

Density of the oil = 100g / 30g = 3.33 g/cm^3

Finally, we can find the relative density of the oil by comparing it to the density of water:

Relative density of the oil = Density of the oil / Density of water

Relative density of the oil = 3.33g/cm^3 / 1g/cm^3 = 3.33

Therefore, the relative density of the oil is 3.33.