Replace names by formulas and indicate oxidation and reduction agents (do not balance reactions).
copper(ll) oxide + CH30H (Iq) ->CH20 (Iq) + cu (s)
To replace names with formulas and identify oxidation and reduction agents, we first need to understand the chemical equation you provided:
Copper(II) oxide + CH3OH(l) -> CH2O(l) + Cu(s)
Now, let's break down the equation and identify the formulas of the compounds involved:
Copper(II) oxide is CuO.
Methanol is CH3OH.
Formaldehyde is CH2O.
Copper is Cu (solid).
To determine the oxidation and reduction agents, we must compare the oxidation states of the elements before and after the reaction.
In CuO, copper is in the +2 oxidation state, and in Cu, copper is in the 0 oxidation state. Therefore, copper has been reduced from +2 to 0.
In CH3OH, carbon is in the -2 oxidation state, and in CH2O, carbon is in the 0 oxidation state. Therefore, carbon has been oxidized from -2 to 0.
Based on these comparisons:
The oxidation agent is methanol (CH3OH) since carbon is being oxidized from -2 to 0.
The reduction agent is copper(II) oxide (CuO) since copper is being reduced from +2 to 0.