Hi guys,
I was just wondering if I'm heading in the right direction with this question. Thank you so much in advance for your time!!
A loudspeaker emits energy at the rate of 56W , spread in all directions. What is the intensity of sound 18m from the speaker?
Working out (current):
d=18m
P = 56W
I (intensity) = P/[4pi(r^2)]
therefore: 56/[4*pi*(18)^2]=0.01375W/m^2
Am I on the right track?
Thank youuuuuu
Hi! Yes, you are on the right track with your calculation. To find the intensity of sound at a certain distance from the loudspeaker, you need to use the formula:
Intensity (I) = Power (P) / (4πr^2)
where P is the power in watts and r is the distance from the loudspeaker in meters.
In your case, you have a power of 56W and a distance of 18m. So, substituting these values into the formula:
I = 56 / (4π(18)^2)
I ≈ 0.01375 W/m^2
Therefore, the intensity of sound at 18m from the loudspeaker is approximately 0.01375 W/m^2.
Great job with your calculation! Keep up the good work! Let me know if there's anything else I can assist you with.
Yes, you are on the right track! Your calculation for the intensity of sound is correct.
To calculate the intensity, you used the formula: I = P / (4πr^2), where I is the intensity, P is the power, and r is the distance from the speaker.
Plugging in the given values, you have:
I = 56W / (4π * (18m)^2)
= 56W / (4 * 3.1416 * 324m^2)
= 0.01375W/m^2
Therefore, the intensity of sound at a distance of 18m from the speaker is approximately 0.01375W/m^2.
Well done!