a car set out at noon to ride from point a to point b, and another car started at 2 pm on the same day to ride from point b to point a. they met on the road at 4:05 pm, and each car reached their destination at exactly the same time. at what time did the car arrive?(hint: both cars are not accelerating).
To solve this problem, we can use the concept of relative speed and distance.
Let's first calculate the time it took for the two cars to meet on the road.
The first car started at noon and met the second car at 4:05 pm. So, the first car traveled for 4 hours and 5 minutes.
The second car started at 2 pm, which means it traveled for 2 hours and 5 minutes.
Next, we need to consider the time it took for each car to reach their destination.
Since both cars took the same amount of time to reach their respective destinations, we can assume that the time it takes for each car to travel from the meeting point to their destinations is the same.
Therefore, the second car traveled for a total of 4 hours and 5 minutes - 2 hours and 5 minutes = 2 hours.
Now, we can determine the time of arrival for the second car:
If the second car started at 2 pm and traveled for 2 hours, it would reach its destination at 4 pm.
Therefore, the car arrived at its destination at 4 pm.