Write and balance each of the following equations, and then identify each by type.
a) copper+chlorine-->copper(ll)chloride
b) calcium chlorate--->calcium chloride+oxygen
c)lithium+water--->lithium hydroxide+hydrogen
d)lead(ll)carbonate--->lead(ll)oxide+carbon dioxide
I don't know how I would even start this question and I have a test soon. Please help! Thanks in advance.:)
You start by knowing the types of chemical reactions.
Do you know what they are?
synthesis
single replacement
decomposition
double replacement.
See your other post above.
No problem! I'll walk you through the steps for balancing each equation.
a) copper + chlorine → copper(II) chloride
To balance this equation, we need to make sure that the number of atoms on each side is equal. Since copper (Cu) is already balanced, let's start with the chlorine (Cl) atoms.
On the left side, we have one chlorine atom, but on the right side, we have two chlorine atoms. To balance the chlorine atoms, we need to place a coefficient of 2 in front of the copper(II) chloride.
The balanced equation is: 2Cu + Cl₂ → 2CuCl₂
Type: Combination reaction
b) calcium chlorate → calcium chloride + oxygen
First, let's count the number of atoms for each element.
On the left side, we have one calcium (Ca) atom, one chlorine (Cl) atom, and three oxygen (O) atoms. On the right side, we have one calcium atom, one chlorine atom, and two oxygen atoms.
To balance the calcium and chlorine atoms, no coefficients are needed. However, we need to add a coefficient of 2 in front of calcium chlorate to balance the oxygen atoms.
The balanced equation is: 2Ca(ClO₃)₂ → 2CaCl₂ + 3O₂
Type: Decomposition reaction
c) lithium + water → lithium hydroxide + hydrogen
Let’s count the number of atoms for each element.
On the left side, we have one lithium (Li) atom and one water (H₂O) molecule. On the right side, we have one lithium atom, one hydroxide (OH⁻) ion, and one hydrogen (H₂) molecule.
To balance the hydrogen atoms, we need to place a coefficient of 2 in front of the H₂O molecule.
The balanced equation is: 2Li + 2H₂O → 2LiOH + H₂
Type: Displacement reaction
d) lead(II) carbonate → lead(II) oxide + carbon dioxide
Let’s count the number of atoms for each element.
On the left side, we have one lead (Pb) atom, one carbon (C) atom, and three oxygen (O) atoms. On the right side, we have one lead atom and two oxygen atoms.
To balance the carbon and oxygen atoms, we need to place a coefficient of 2 in front of the lead(II) carbonate.
The balanced equation is: PbCO₃ → PbO + CO₂
Type: Decomposition reaction
Remember, when balancing equations, you want to start by balancing the atoms of elements that appear in only one reactant and only one product. Then, balance the atoms of elements that appear in multiple reactants and/or products as needed. The goal is to have the same number of atoms of each element on both sides of the equation.