How many milliliters of 0.950M sodium hydroxide must be added to 35.0mL of 0.850M acetic acid to reach the equivalence point?
should the volume of the hydroxide be the same as the volume of the acid because there is a 1:1 ratio? If so, how do I set up an equation or ICE table to figure this out?
If the molarity is the same then the volume will be the same; however, the M is not the same.
You want mols acetic acid = mols NaoH.
That will be the equivalence point.
mols acetic acid = M x L = ?
Then mols NaOH = mols acetic acid.
Finally M NaOH = mols NaOH/L NaOH. You know M NaOH and mols NaOH, solve for L NaOH and convert to mL.