A volleyball is served at an angle of 35 degrees with an initial speed of 5 m/s. What is the maximum height reached by the ball?
Vo = 5m/s[35o]
Yo = 5*sin35 = 2.87 m/s.
Y^2 = Yo^2 + 2g*h = 0
h = -Yo^2/2g = -(2.87)^2/-19.6 = 0.42 m
compute for the range of the volleyball when it was served at an angle 50° to the horizontal with an initial velocity of 35 m/s.
Why did the volleyball go to such great heights? It was just trying to reach the "spike" of its career!
But in all seriousness, to find the maximum height reached by the ball, we can use the equation for projectile motion. The maximum height can be calculated using the formula:
H = (V^2 * sin^2 θ) / (2 * g)
where:
H is the maximum height,
V is the initial velocity (5 m/s),
θ is the angle of projection (35 degrees),
and g is the acceleration due to gravity (9.8 m/s^2).
Plugging in the values, we get:
H = (5^2 * sin^2 35) / (2 * 9.8)
H = (25 * (0.574)^2) / (19.6)
H ≈ 0.586 meters
So, the maximum height reached by the ball is approximately 0.586 meters. Keep reaching for the stars, volleyball!
To find the maximum height reached by the ball, we need to analyze the vertical motion of the volleyball.
The initial speed can be broken down into its horizontal and vertical components. The vertical component of the initial velocity is given by:
V0y = V0 * sin(angle)
where V0 is the initial speed and angle is the angle at which the ball is served.
In this case, V0 = 5 m/s and angle = 35 degrees.
V0y = 5 * sin(35)
≈ 5 * 0.5736
≈ 2.868 m/s
The maximum height reached by the ball can be found using the following formula:
H = (V0y^2) / (2 * g)
where H is the maximum height and g is the acceleration due to gravity, approximately 9.8 m/s^2.
Now, let's calculate the maximum height reached by substituting the values:
H = (2.868^2) / (2 * 9.8)
≈ 8.262 / 19.6
≈ 0.421 m
Therefore, the maximum height reached by the ball is approximately 0.421 meters.
A volleyball is served at an angle of 35 degrees with an initial speed of 5 m/s. What is the maximum height reached by the ball?
how find the maximum