posted by Jason
A 20.0-mL sample of 0.300 M HBr is titrated with 0.150 M NaOH. What is the pH of the solution after 40.3 mL of NaOH have been added to the acid?
Write and balance the equation.
mols HBr = M x L = ?
mols NaOH = M x L = ?
Which reactant is in excess.
If HBr, the pH = -log(HBr)
If NaOH, the pOH = -log(NaOH) and pH + pOH = pKw = 14.