posted by Jason

A 20.0-mL sample of 0.300 M HBr is titrated with 0.150 M NaOH. What is the pH of the solution after 40.3 mL of NaOH have been added to the acid?

  1. DrBob222

    Write and balance the equation.
    mols HBr = M x L = ?
    mols NaOH = M x L = ?

    Which reactant is in excess.
    If HBr, the pH = -log(HBr)
    If NaOH, the pOH = -log(NaOH) and pH + pOH = pKw = 14.

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