An inclined plane rises to aheight of 2 m over adistance of 6 m. Calculate: 1.The ange of the slope 2.The VR (and so IMA) of the inclined plane. 3The theoretical force required to push an object with a mass of 200 Kg up the slope.
angle=arc tan (2/6)
IMA=3
normal force=mg=200*9.8 Newtons
theoretical force=1/3 * 200*9.8 N
1.0.34 2.3 3.653.34
answer
siraj
answer
A) The angle of slope Teta?
B) VR=? (IMA)
C) E=?(m=2ookg)
To calculate the answers to your questions, we can use the formulas and concepts related to inclined planes.
1. The angle of the slope:
The angle of inclination can be calculated using the formula:
Angle = arctan(height/distance)
In this case, the height is 2 m and the distance is 6 m. Plugging those values into the formula, we get:
Angle = arctan(2/6)
Calculating this value, we find that the angle of the slope is approximately 18.43 degrees.
2. The VR (and so IMA) of the inclined plane:
The VR (Velocity Ratio) refers to the ratio of the distance traveled along the inclined plane to the vertical distance in the same direction. It is also commonly known as the mechanical advantage (MA). The formula to calculate VR is:
VR = distance traveled along the inclined plane / vertical distance
In this case, the distance traveled along the inclined plane is 6 m and the vertical distance is 2 m. Plugging those values into the formula, we get:
VR = 6/2 = 3
So, the VR (and IMA) of the inclined plane is 3.
3. The theoretical force required to push an object with a mass of 200 kg up the slope:
To calculate the force required, we need to consider the weight of the object and the angle of the slope. The formula to calculate the force required is:
Force = mass * gravity * sin(angle)
In this case, the mass is 200 kg, the acceleration due to gravity is approximately 9.8 m/s^2, and the angle is 18.43 degrees. Plugging those values into the formula, we get:
Force = 200 * 9.8 * sin(18.43)
Calculating this, we find that the theoretical force required to push the object up the slope is approximately 590.59 N (Newton).