three balls are drawn successively from a box containing 6 red balls,4white balls and 5 blue balls. find the probability that tare hey drawn in the order red,white and blue if each ball is replaced?
i dunno can you tell me
Ans the question ðŸ˜ðŸ˜’🙄
To find the probability of drawing three balls in the order red, white, and blue with replacement, we need to consider the probability of each step in the drawing process.
Step 1: Drawing a red ball.
The probability of drawing a red ball is the number of red balls divided by the total number of balls:
P(Red) = 6 (number of red balls) / 15 (total number of balls) = 6/15 = 2/5
Step 2: Drawing a white ball.
Since each ball is replaced after drawing, the probability of drawing a white ball is the same as the probability of drawing a red ball:
P(White) = P(Red) = 2/5
Step 3: Drawing a blue ball.
Again, the probability of drawing a blue ball is the same as the probability of drawing a red or white ball since each ball is replaced:
P(Blue) = P(Red) = 2/5
Now, to find the probability of drawing the balls in a specific order (red, white, blue), we multiply the probabilities of each step together:
P(Red, White, Blue) = P(Red) * P(White) * P(Blue)
= (2/5) * (2/5) * (2/5)
= 8/125
Therefore, the probability of drawing three balls in the order red, white, and blue, with replacement, is 8/125.
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If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
6/15 * 4/15 * 5/15 = ?