Emma's school plans to build a rectangular basketball court with an area of 150+175t square feet. The length of the basketball court is 25 feet as shown in the following diagram.
Thank you!
And the question is?
SORRY.. here is the question...
What is the width of the basketball court?
I am not certain what you mean by an area of 150+175t.
25*W=area
solve for W.
The answer should be 175 * 25 + 150
First of all, lets note what the formula is.
A=bh or lw
25 is the width so lets plug it in.
25w=150+175t
Next, you evaluate that by Isolating the "w". Divide the 25 by 25 and divide 150+175t to get 6+7t
Get rekt noob........
You're welcome! However, I do not have access to see the diagram you mentioned. Nevertheless, I can still help you with the problem statement you provided.
To find the width of the rectangular basketball court, we need to use the formula for the area of a rectangle, which is given by:
Area = Length × Width
We know that the area of the basketball court is given by 150 + 175t square feet, and the length is given as 25 feet. So, let's substitute these values into the formula and solve for the width.
150 + 175t = 25 × Width
To isolate the width, we divide both sides of the equation by 25:
(150 + 175t) / 25 = Width
Simplifying the equation:
6 + 7t = Width
Thus, the width of the rectangular basketball court is 6 + 7t feet.