A given mass of air has a volume of 6.0l at 1 atom.what volume will it occupy at 190mm hg if the temperature does not change?

To calculate the volume of air at a different pressure, we can use Boyle's law, which states that the volume of a gas is inversely proportional to its pressure when the temperature remains constant.

Boyle's law equation can be written as: P1 * V1 = P2 * V2

Where:
P1 = initial pressure (1 atm)
V1 = initial volume (6.0 L)
P2 = final pressure (190 mmHg)
V2 = final volume (unknown)

First, we need to convert the final pressure from mmHg to atm, as Boyle's law requires pressures to be in the same unit. The conversion factor from mmHg to atm is 1 atm = 760 mmHg. Therefore, we have:
P2 = 190 mmHg / 760 mmHg/atm
P2 = 0.25 atm

Now, we can solve for V2 by rearranging the equation:
P1 * V1 = P2 * V2

Substituting the known values:
(1 atm) * (6.0 L) = (0.25 atm) * V2

Simplifying the equation:
6.0 L = 0.25 * V2

To isolate V2, divide both sides of the equation by 0.25:
V2 = (6.0 L) / 0.25
V2 = 24 L

Therefore, the air will occupy a volume of 24 liters at a pressure of 190 mmHg, assuming the temperature remains constant.