What is the mass in grams of 24.32 moles of CaCO3?

So far I got:

24.32mol CaCO3 x 100.09gCaCO3 / 1mol CaCO3 =

I am not sure if this is correct, because I got a really big number and I feel like I am missing something in the question.

You aren't missing anything. You are right on. Thanks for showing your work. When you do that it takes just a glance to know if things are ok.

oh ok thanks! also should I put the answer in scientific notation?

It depends upon how many significant figures you are reporting. You are allowed 4 and I get 24.32 x 100.09 = 2434.189 so you can legitimately report 2434 g with 4 places. There is nothing wrong with reporting it as 2.434E3 grams.

You're on the right track! To calculate the mass in grams of CaCO3, you can use the given number of moles and the molar mass of CaCO3.

The molar mass of CaCO3 is the sum of the atomic masses of its constituent elements: calcium (Ca), carbon (C), and oxygen (O).

To calculate the molar mass of CaCO3:
Ca: 1 atom x atomic mass of Ca = 1 x 40.08 g/mol = 40.08 g/mol
C: 1 atom x atomic mass of C = 1 x 12.01 g/mol = 12.01 g/mol
O: 3 atoms x atomic mass of O = 3 x 16.00 g/mol = 48.00 g/mol

Adding these up, you get:
40.08 g/mol + 12.01 g/mol + 48.00 g/mol = 100.09 g/mol

Now, to find the mass in grams of 24.32 moles of CaCO3, you can use the conversion factor you mentioned:

24.32 mol CaCO3 x 100.09 g CaCO3/ 1 mol CaCO3 = 2434.1928 g CaCO3

So, the mass of 24.32 moles of CaCO3 is approximately 2434.1928 grams.