What value of y makes the following system of equations true?

3x + 6y=12
5x + 6y = 4

If you subtract the second equation from the first, you get:

-2x = 8

x = -4

Substitute that into either equation to find the value of y.

To find the value of y that makes the system of equations true, we need to solve for y using the given equations.

First, let's eliminate the x variable by subtracting the second equation from the first equation:

(3x + 6y) - (5x + 6y) = 12 - 4

This simplifies to:
-2x = 8

Now, we can solve for x by dividing both sides of the equation by -2:

x = -4

Next, we substitute this value of x into one of the original equations. Let's use the first equation:

3x + 6y = 12

Substituting x = -4:

3(-4) + 6y = 12

Simplifying further:

-12 + 6y = 12

Add 12 to both sides:

6y = 24

Now, divide both sides of the equation by 6 to solve for y:

y = 4

Thus, the value of y that makes the system of equations true is y = 4.