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. A body with a mass of 490kg is pulled along a horizontal plane at a constant velocity.the pulling force is 1.2 kN is making an angle of 20degrees with the plane.
A.determine the coefficient of friction
pak
To determine the coefficient of friction, we need to use the formula for frictional force:
Frictional force = coefficient of friction * normal force
In this case, since the body is pulled along a horizontal plane with a constant velocity, we know that the force of friction must be equal (but in the opposite direction) to the pulling force. Therefore, we can set up the following equation:
Frictional force = Pulling force
Now, we need to calculate the frictional force. The pulling force is given as 1.2 kN, which is equivalent to 1.2 * 1000 N = 1200 N.
Next, we need to calculate the normal force. The normal force is the force exerted by the surface on the body, perpendicular to the plane. Since the body is on a horizontal plane, there is no vertical acceleration, and thus the normal force is equal to the weight of the body.
Weight = mass * acceleration due to gravity
Given that the mass is 490 kg and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the weight:
Weight = 490 kg * 9.8 m/s^2 = 4802 N
Since the surface is horizontal, the normal force is equal to the weight of the body. Therefore, the normal force is 4802 N.
Now, we can substitute the values into the equation for frictional force:
Frictional force = coefficient of friction * normal force
1200 N = coefficient of friction * 4802 N
Finally, we can solve for the coefficient of friction:
coefficient of friction = 1200 N / 4802 N ≈ 0.25
Therefore, the coefficient of friction is approximately 0.25.