Can someone tell me if I did this combined gas law problem correctly?
What would happen to the volume of a container whose initial volume is 21.5 L at STP (standard pressure) and is introduced to conditions of 93.2 kPa and 333 K?
Formula: P1 x V1 / T1 = P2 x V2 / T2
V2 = P1 x V1 x T2 / P2 x T1
My work:
V1 = 21.5 L
T1 = 333 K
P1 = 93.2 kPa
T2 = 273 K
P2 = 101.3 kPa
V2 = 93.2 kPa x 21.5 L x 273 K 547037
------------------------------- = ________
101.3 kPa x 333 K 33732.9
Final Answer = 16.2167
No, you have the right formula and your algebra is right but you didn't assign the values correctly. You problem states you have 21.5L at STP so V1 is 21.5, T1 is 273 and P1 is 101.325. You are changing the conditions to 93.2 kPa so that is P2 and to temp of 333 K so that is T2.
To verify if you did the combined gas law problem correctly, let's go through the steps together:
Step 1: Write down the given information:
V1 (initial volume) = 21.5 L
T1 (initial temperature) = 333 K
P1 (initial pressure) = 93.2 kPa
T2 (final temperature) = 273 K
P2 (final pressure) = 101.3 kPa
Step 2: Use the formula for the combined gas law:
P1 x V1 / T1 = P2 x V2 / T2
Step 3: Rearrange the formula to solve for V2:
V2 = P1 x V1 x T2 / P2 x T1
Step 4: Substitute in the given values into the formula:
V2 = (93.2 kPa x 21.5 L x 273 K) / (101.3 kPa x 333 K)
Step 5: Perform the calculations:
V2 = 547037 / 33732.9
Now let's calculate the final answer:
V2 = 16.2167 L
Based on your calculations, you indeed obtained the correct answer for the final volume. The final volume will be 16.2167 L when the initial volume of 21.5 L at STP is introduced to conditions of 93.2 kPa and 333 K.
Great job!