It's an irregular hexagon. The base of the hexagon is 12m, the length of one side is 9m, the length of the other sides are 5m, and 4m, the width of the other sides are 7m and 5m.
What is the area of the hexagon ?
Maria, as I told you yesterday, you don't have enough information
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To find the area of an irregular hexagon, we can split it into trapezoids and triangles and calculate the area of each individual shape.
First, let's calculate the area of the trapezoid formed by the base of the hexagon, which has a length of 12m. The width of the trapezoid is 7m, so we can use the formula for the area of a trapezoid:
Area = (base1 + base2) * height / 2
Since base1 = base2 = 12m and the height = 7m, we can substitute these values into the formula:
Area1 = (12m + 12m) * 7m / 2 = 84m²
Next, let's calculate the area of the triangle formed by the side length of 9m and the width of 7m. The formula for the area of a triangle is:
Area = base * height / 2
In this case, the base = 9m and the height = 7m, so we can calculate the area of this triangle:
Area2 = 9m * 7m / 2 = 31.5m²
Now, let's calculate the area of the triangle formed by the side length of 9m and the width of 5m:
Area3 = 9m * 5m / 2 = 22.5m²
Finally, let's calculate the area of the triangle formed by the side length of 9m and the width of 4m:
Area4 = 9m * 4m / 2 = 18m²
Now, we can sum up the areas of all the shapes to find the total area of the irregular hexagon:
Total Area = Area1 + Area2 + Area3 + Area4
= 84m² + 31.5m² + 22.5m² + 18m²
= 156m²
Therefore, the area of the irregular hexagon is 156 square meters.