posted by Wendy
When 80.0 mL of HCl is added to 80.0 mL of NH3OH, the temperature increases 2.5 celsius. Assuming the final solution has the same specific heat capacity as liquid water, the heat produced in the reaction between two solutions is:
I don't know how to find the moles and mass
80 mL + 80 mL = 160 mL aqueous solution. If you assume the density is the same as that of water;i.e., 1.00 g/mL, than the mass is 160 grams.. The specific heat h2O is 4.184 so
q = 160 x 4.184 x 2.5 = ? in J.
BTW, I think you meant NH4OH (and technically that is NH3(aq)
Oh yes sorry I did mean NH4OH, how do I find the moles?