A poor farmer is going to market with his faithful hungry dog, two plump geese to sell, and three bags of corn. The farmer knows that unless he is right there, the dog will eat a goose or a goose will eat some corn. Traveling carefully, he avoids trouble until he comes to a small river which he must ferry across. there is a creaky old rowboat that is in such bad shape it will only hold him and any of two of the six things at one time. How many times does the farmer need to cross the river to get all of his possessions safely to the other side? Please help me pls
7 times
trip 1: both geese across the river
trip 2: cross alone back to the original side
trip 3: dog and one bag of corn to other side
trip 4: both geese back again to original side
trip 5: remaining two bags of corn to other side
trip 6: back across river alone to original side
trip 7: both geese to other side, completing the task of all items to the other side
This is a tricky question but I think I understand
1 trip, both geese
2. two bags of corn, but he has to take the geese back with him
3. the dog and the other bag of corn
4. He has to go back to get the geese
So he need to cross the river eight times.
thank u so much esp cory and morgan
To solve this puzzle, we need to figure out how the farmer can transport all his possessions across the river while ensuring that the dog doesn't eat the geese or the geese don't eat the corn. Here's a step-by-step explanation of how the farmer can do it:
1. The first thing the farmer should do is take the two geese across the river. He leaves one goose on the other side and returns alone.
- Farmer + 2 geese ↔︎ Dog + 3 corn
2. The farmer then takes the dog across the river but brings one goose back.
- Farmer ↔︎ Dog + 2 geese + 3 corn
3. Now, the farmer takes both the bags of corn across the river.
- Farmer + 2 corn ↔︎ Dog + 2 geese
4. The farmer leaves one bag of corn on the other side and takes the goose back.
- Farmer + 1 corn ↔︎ Dog + 3 geese
5. The farmer now leaves the goose on the original side and takes the dog across the river.
- Farmer ↔︎ Dog + 3 geese + 1 corn
6. Finally, the farmer goes back alone and brings the remaining two geese across the river.
- Farmer + 2 geese ↔︎ Dog + 1 corn
7. The farmer leaves the two geese on the other side and takes the corn across the river.
- Farmer + 1 corn ↔︎ Dog + 2 geese
8. Finally, the farmer goes back alone and brings the last remaining goose across the river.
- Farmer ↔︎ Dog + 3 geese + 1 corn (all safely on the other side)
Summing up, the farmer needs to cross the river a total of 8 times to get all his possessions safely to the other side.