You begin pushing the car forward from rest. Assume that your car has a mass of 809 kg. Neglecting friction, how long will it take you to push your car up to a speed of 3.93 m/s on a level surface if you exert a constant force of 218 N on it?

Well, pushing a car is no joke, but I'll try to make it entertaining.

Let's calculate the time it takes to push your car up to that speed using a little physics and a lot of silliness. Ready?

First, we need to use Newton's second law of motion: force equals mass times acceleration. In this case, your force is 218 N, and your car's mass is 809 kg. So,

218 N = 809 kg × acceleration

Now we need to solve for acceleration. Dividing both sides of the equation by 809 kg:

acceleration = 218 N / 809 kg

After dividing those numbers, we get a rather ugly decimal. Instead of giving you the exact value, I'll just say it looks like a frog stepped on a calculator. Let's call it "Quack-acceleration."

Now, let's imagine a raccoon hopping on a trampoline. That raccoon represents your car's acceleration. With each bounce, it goes higher and faster. You want your raccoon to reach a final speed of 3.93 m/s. How long does it take? Well, raccoons are quite clever, but they aren't known for their speed, so let's figure it out.

We can use another formula: final speed equals initial speed plus acceleration times time. In this case, our initial speed is 0 m/s, and our final speed is 3.93 m/s. Let's call the time it takes for our raccoon to reach that speed "Tumble-bounce time."

3.93 m/s = 0 m/s + Quack-acceleration × Tumble-bounce time

Now we can solve for Tumble-bounce time:

Tumble-bounce time = (3.93 m/s - 0 m/s) / Quack-acceleration

When you divide, you'll get another crazy decimal. I'll call it "Tumble-quack time."

So, to put it all together, it will take you Tumble-quack time to push your car up to 3.93 m/s. Just remember, this is all hypothetical and doesn't account for friction or real-life conditions. But who knew physics could be so amusing? Enjoy your raccoon-pushing adventures!

To find the time it takes to accelerate the car to a speed of 3.93 m/s, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

Given:
Mass of the car (m) = 809 kg
Force exerted on the car (F) = 218 N
Final velocity (v) = 3.93 m/s

We can assume that there is no initial velocity (starting from rest), and neglecting friction, the net force on the car is equal to the force exerted.

Using Newton's second law, we can calculate the acceleration (a):
F = m * a
a = F / m
a = 218 N / 809 kg
a ≈ 0.269 m/s²

Next, we can use the equation for acceleration to find the time (t) it takes for the car to reach the final velocity:
v = u + a * t
Where:
u = initial velocity (0 m/s)

Since we are starting from rest, the equation simplifies to:
v = a * t
t = v / a
t = 3.93 m/s / 0.269 m/s²
t ≈ 14.6 seconds

Therefore, it will take approximately 14.6 seconds to push the car up to a speed of 3.93 m/s on a level surface, neglecting friction.

To find the time it takes to accelerate the car to a certain speed, we can use Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration.

First, we need to calculate the acceleration of the car. Since the only force acting on the car is the force applied by pushing it, the acceleration can be found using the formula:

acceleration = force / mass

Given:
Force (F) = 218 N
Mass (m) = 809 kg

Plugging the values into the formula, we have:

acceleration = 218 N / 809 kg
acceleration ≈ 0.269 m/s²

Now, we can calculate the time it takes to reach the desired speed of 3.93 m/s using the formula:

time = (final velocity - initial velocity) / acceleration

Given:
Initial velocity (u) = 0 m/s
Final velocity (v) = 3.93 m/s
Acceleration (a) ≈ 0.269 m/s²

Plugging the values into the formula, we have:

time = (3.93 m/s - 0 m/s) / 0.269 m/s²
time ≈ 14.60 s

Therefore, it will take approximately 14.60 seconds to push the car up to a speed of 3.93 m/s on a level surface.

Use

F = ma
and
v = u + at

F = force
m = mass
a = acceleration
v = final velocity
u = initial velocity
t = time