a solid X, insoluble in water, weighs 180g in air and 150g in water. what is the relative density of the solid X?
it is the physics question.
densityX=180/v
in water, bouyant force=densitywater*V
or
density water=30/V
So relative density=180/30=6
densityX=180/v
in water, bouyant force=densitywater*V
or
density water=30/V
So relative density=180/30=6
To find the relative density (also known as the specific gravity) of the solid X, we can use the formula:
Relative Density = (Weight in Air) / (Weight in Water)
Given that the weight of the solid X in air is 180g and the weight in water is 150g, we can substitute these values into the formula:
Relative Density = 180g / 150g
Now we can simplify the expression:
Relative Density = 1.2
Therefore, the relative density of the solid X is 1.2.
To find the relative density of solid X, we need to use the formula:
Relative Density = (Weight in Air) / (Weight in Air - Weight in Water)
Given that the weight of solid X in air is 180g and the weight in water is 150g, we can substitute these values into the formula:
Relative Density = 180g / (180g - 150g)
Simplifying further:
Relative Density = 180g / 30g
Relative Density = 6
Therefore, the relative density of solid X is 6.