Calculate the extension that would be produced by a 20N force if 15N extends a spring by 3cm
x/3=20/15
x=4cm
Calculate the extence of spring that would be produced by a 20N load extends the spring by 3cm?
X=7.5m
To prepare for an exam
To calculate the extension produced by a given force on a spring, we need to use Hooke's Law, which states that the extension of a spring is directly proportional to the force applied to it.
Hooke's Law equation is:
F = k * x
Where:
- F is the force applied to the spring.
- k is the spring constant, which represents the stiffness of the spring.
- x is the extension produced by the force.
First, let's calculate the spring constant (k):
k = F / x
Given that a force of 15N extends the spring by 3cm, we have:
F = 15N
x = 3cm = 0.03m
Substituting these values into the equation, we can find k:
k = 15N / 0.03m
k = 500N/m
Now that we have the spring constant, we can calculate the extension (x) produced by a 20N force.
Using the rearranged Hooke's Law equation:
x = F / k
Substituting the values:
F = 20N
k = 500N/m
x = 20N / 500N/m
x = 0.04m
Therefore, a 20N force would produce an extension of 0.04m (or 4cm) on the spring.